3x^2+7x-9=3-9x

Solution for 3x^2+7x-9=3-9x equation:

3x^2+7x-9=3-9x

We move all terms to the left:

3x^2+7x-9-(3-9x)=0

We add all the numbers together, and all the variables

3x^2+7x-(-9x+3)-9=0

We get rid of parentheses

3x^2+7x+9x-3-9=0

We add all the numbers together, and all the variables

3x^2+16x-12=0

a = 3; b = 16; c = -12;
Δ = b2-4ac
Δ = 162-4·3·(-12)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-20}{2*3}=\frac{-36}{6}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+20}{2*3}=\frac{4}{6}
=2/3
$